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General Area FormulaDate: 02/14/2002 at 22:46:39 From: Will Voorhees Subject: General Area Formula I heard that there was an all-inclusive formula for the area of a square, rectangle, parallelogram, trapezoid, and triangle. Is this true? I have looked everywhere, but I can't find anything.
Date: 02/15/2002 at 11:01:29
From: Doctor Ian
Subject: Re: General Area Formula
Hi Will,
Let's start with the most complicated (i.e., least symmetric) shape,
which is a trapezoid:
a
________
/ \ area = height * (a+b)/2
/__________\
b
In the case where a and b are equal, we have a parallelogram:
a
___________
/ / area = height * (a+b)/2
/__________/
b
And the formula still works. Note that when a = b,
(a+b)/2 = (b+b)/2
= 2*b/2
= b
If we make all the angles square, we have a rectangle:
a
_________
| | area = height * (a+b)/2
|_________|
b
And the formula still works. If we make the width the same as the
height, we have a square:
a (= h)
___
| | area = height * (a+b)/2
|___|
b
And the formula still works! The principal difference is that when you
have a rectangle or a square, the height is trivial to find; while
when you have a trapezoid or a parallelogram, the process can be
somewhat more involved.
So, what about a triangle? Well, if we draw the triangle so that the
base is horizontal,
a a
/\ /| a
/ \ / | . /
/ \ / | . /
/______\ /___| _____/
b b b
then the value of the 'top base', a, is zero, so the formula gives us
area = height * (a+b)/2
= height * (0+b)/2
= (1/2) height * b
So it works for a triangle, too - if you're willing to define a
triangle as a quadrilateral with one zero-length side.
I hope this helps. Thanks for an interesting question!
- Doctor Ian, The Math Forum
http://mathforum.org/dr.math/
Date: 02/15/2002 at 22:46:24
From: Will Voorhees
Subject: General Area Formula
Thanks for the reply! This really helped me a lot.
William Voorhees
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