|
|
Re: I don't understand -- Matlab/Maple refused compute the Taylor expansion of this function?
Posted:
Sep 1, 2006 2:07 PM
|
|
Robert Israel wrote: > In article <1157052597.072155.300000@74g2000cwt.googlegroups.com>, > Luna Moon <lunamoonmoon@gmail.com> wrote: > > >I found everything now is very complicated... I need time to digest > >what you said. I have never heard about the "outside residue theorem" > >and "branch cut not being a straight line". Regular complex analysis > >class never taught me these stuffs... could you please recommend some > >readings about what you've used in your great tricks? I found it > >difficult to follow the a few lines here, I have to read more > >extensively ... > > You might try e.g. Marsden and Hoffman, "Basic Complex Analysis". > What I called the "outside residue theorem" is Proposition 4.2.4 > in that book. > > >For now I just have a quick question about the last statement you've > >made: "it is not possible to do it with the residue theorem", then is > >there still a way to evalute the contour? > > I don't see any way off-hand. Of course you could always use > numerical integration. >
Thanks a lot Robert! I have a question about the non-straight branch cuts and branch points at the infinity.
Do you mean if I have two branch points at -i and -1/3i, I cannot just specify my branch cut be a curve that connects the two points, instead of letting the branch cut go straight to the infinity?
If I have three branch points, do I have a way to wrap all my branch cuts inside a small region enclosing all these three branch points? That's to say, I hope there is a way to restrict the trouble of handing the branch cuts to within a small region...
Moreover, if I want to integrate
Integrate( (2-z^(-1))^(-sqrt(2)), z on a contour along |z|=1),
so there is a branch point z=1/2 inside the contour |z|=1, is there a way to integrate it?
Thanks again!
|
|